2021 JPJC Promo Q8
2021 JPJC Promo Q8
4 marks
Promo
The height of an upright cone is twice the radius, \(r\), of its circular base. It is known that the volume of the cone is increasing at the rate of \(15\) cm\(^{3}\)min\(^{-1}\) when the radius is \(3\) cm. Find the rate of increase of the base area of the cone at this instant.
[4]
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Answer:\(5\)cm\(^{2}\)min\(^{-1}\)
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