2021 EJC Promo Q1
2021 EJC Promo Q1
5 marks
Promo
A curve \(C\) has equation
\(5{{y}^{2}}-20xy+25{{x}^{2}}-5y-6=0\).
Find the exact \(x\)-coordinates of the stationary points of \(C\).[5]
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Answer:\(x=-\frac{2}{5}\) or \(\frac{12}{5}\)
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