2021 CJC Promo Q1

2021 CJC Promo Q1

3 marks
Promo

The diagram shows the curve \(y=\mathrm{f}\left( x \right)\). The curve has an asymptote \(y=0\) and a maximum point at \(\left( 2,3 \right)\). It is given that \(\mathrm{f}\) is concave downwards for \(1\le x\le 3\).

Sketch the graph of \(y=\mathrm{f}'\left( x \right)\), stating the equations of any asymptotes, the \(x\)-coordinates of any stationary points and any points of intersection with the \(x\)-axis.[3]

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Answer:The graph of \(y=\mathrm{f}'(x)\) has horizontal asymptote \(y=0\), a maximum stationary point at \(x=1\), a minimum stationary point at \(x=3\), and an \(x\)-intercept at \((2,0)\)

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