2021 ASRJC Promo Q12

2021 ASRJC Promo Q12

13 marks
Promo

Relative to the origin \(O\), a point \(A\) has position vector \(-\mathbf{j}+2\mathbf{k}\). The plane \({{p}_{1}}\) has equation \(\mathbf{r}\cdot \left( \begin{matrix} 1 \\-1 \\0 \end{matrix} \right)=3\).

  1. Find the position vector of the foot of perpendicular from point \(A\) to the plane \({{p}_{1}}\).[4]

The line \(l\) has equation \(\mathbf{r}=\left( \begin{matrix} 0 \\-1 \\2 \end{matrix} \right)+\mu \left( \begin{matrix}0 \\1 \\1 \\ \end{matrix} \right)\),\(\mu \in \mathbb{R}\).

  1. Find the acute angle between the plane \({{p}_{1}}\) and the line \(l\).[2]
  2. The point \(B\left( -\alpha ,2,\alpha \right)\) is equidistant from the plane \({{p}_{1}}\) and the line \(l\). Find the possible values of \(\alpha \).[4]

The plane \({{p}_{2}}\) has equation \(\mathbf{r}\cdot \left( \begin{matrix} 1 \\1 \\-1 \end{matrix} \right)=5-\beta \), \(\beta \ne 8\).

  1. Show that the point \(C\left( 4,1,\beta \right)\) lies on both \({{p}_{1}}\) and \({{p}_{2}}\). Hence find the vector equation of the line of intersection between the planes \({{p}_{1}}\) and \({{p}_{2}}\)[3]

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Answer:(i) \( \overrightarrow{OF}=\left( \begin{matrix} 1 \\ -2 \\ 2 \\ \end{matrix} \right) \) (ii) \( \theta ={{30}^{\circ }}\) (iii) \( \alpha =0\) or \(10\) (iv) \( \mathbf{r}=\left( \begin{matrix} 4 \\ 1 \\ \beta \\ \end{matrix} \right)+\gamma \left( \begin{matrix} 1 \\ 1 \\ 2 \\ \end{matrix} \right)\), \( \gamma \in \mathbb{R}\)

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