2021 ACJC Promo Q6

2021 ACJC Promo Q6

7 marks
Promo

The Cartesian equation of line \({{L}_{1}}\) is \(\frac{x-2}{a}=\frac{y+2}{b}=\frac{z-3}{c}\), where \(a\), \(b\), \(c\) are constants.

The line \({{L}_{2}}\) is parallel to the vector \(4\mathbf{i}+3\mathbf{j}\). The line \({{L}_{3}}\) passes through the origin and the point with position vector \(\mathbf{j}+\mathbf{k}\).

  1. Given that \({{L}_{1}}\) is perpendicular to \({{L}_{2}}\), form an equation relating \(a\) and \(b\).[1]
  2. Given that \({{L}_{1}}\) intersects \({{L}_{3}}\), show that \(5a+2b-2c=0\).[3]
  3. Hence express \(a\) and \(b\) in terms of \(c\).[1]
  4. Find the acute angle between \({{L}_{1}}\) and \({{L}_{3}}\).[2]

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Answer:(i) \(4a+3b=0\) (iii) \(-\frac{8}{7}c\) (iv) \(86.7^\circ \)

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