2021 ACJC Promo Q10

2021 ACJC Promo Q10

12 marks
Promo

Referred to the origin \(O\), the points \(A\), \(B\) and \(C\) have position vectors \(4\mathbf{i}-2\mathbf{j}\), \(\alpha \mathbf{i}-\mathbf{j}+2\mathbf{k}\) and \(-\mathbf{i}-7\mathbf{j}+\beta \mathbf{k}\) respectively, where \(\alpha \) and \(\beta \) are constants.

  1. Given that \(A\), \(B\) and \(C\) are collinear, show that \(\alpha =5\), and find the value of \(\beta \).[3]

The plane \(\pi \) contains the line \(L\), which has equation \(\mathbf{r}=2\mathbf{i}+3\mathbf{j}+\mu \left( 2\mathbf{i}-\mathbf{j}+\mathbf{k} \right)\). The plane \(\pi \) is also parallel to the line that passes through the points \(A\) and \(B\).

  1. Find the shortest distance from point \(A\) to the line \(L\).[2]
  2. Show that the cartesian equation of the plane \(\pi \) is \(x+y-z=5\).[2]
  3. Find the position vector of the foot of the perpendicular from point \(A\) to the plane \(\pi \).[3]
  4. Hence find the reflection of the line that passes through points \(A\) and \(B\) about the plane \(\pi \).[2]

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Answer:(i) \(\alpha=5,\ \beta=-10\) (ii) \(\displaystyle \sqrt{\frac{31}{2}}\text{ units}\) (iii) \(\pi:x+y-z=5\) (iv) \(\displaystyle \overrightarrow{OF}=\begin{pmatrix}5\\ -1\\ -1\end{pmatrix}\) (v) \(\displaystyle \mathbf{r}=\begin{pmatrix}6\\ 0\\ -2\end{pmatrix}+\lambda\begin{pmatrix}1\\ 1\\ 2\end{pmatrix}\), \(\lambda\in\mathbb{R}\)

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