2021 ACJC P1 Q3

2021 ACJC P1 Q3

9 marks
Prelims

The function \(\mathrm{f}\) is defined as \(\mathrm{f}:x\mapsto \frac{a}{2-x}\), \(x\in \mathbb{R}\), \(x\ne 0,2\).

  1. Find \({{\mathrm{f}}^{2}}\) and \({{\mathrm{f}}^{-1}}\) in terms of \(a\), stating their domains clearly.[5]
  2. Find the value of \(a\) such that \({{\mathrm{f}}^{2}}\left( x \right)={{\mathrm{f}}^{-1}}\left( x \right)\) for all \(x\in \mathbb{R}\), \(x\ne 0,2,\frac{a}{2}\).[2]
  3. Using the value of \(a\) found in (ii), find \({{\mathrm{f}}^{2021}}\left( x \right)\).[2]

Video Solution:

Video Solution

Video solution locked

A free account saves your progress; this video needs a course plan.

Solution:

Solution locked

680+ questions here come with free worked solutions. A free account saves your questions and progress; this one needs a course plan.

Answer:(i) \(f^2:x\mapsto\frac{a(2-x)}{4-a-2x}\), \(f^{-1}:x\mapsto2-\frac ax\); (ii) \(a=4\); (iii) \(f^{2021}(x)=2-\frac4x\)

Need help? Join our JC Math tuition classes.

Learn more