The points \(A\) and \(B\) have positions vectors \(\mathbf{i}-2\mathbf{j}-\mathbf{k}\) and \(s\mathbf{i}+t\mathbf{j}-4\mathbf{k}\) respectively. The plane \(p\) has equation \(3x-2y-z=5\). Given that the line \(AB\) has no points in common with the plane \(p\), express \(s\) in terms of \(t\).[2]
Find the shortest distance between the line \(AB\) and the plane \(p\).[2]
Another plane \(q\) is perpendicular to plane \(p\) and contains the line with equation \(\frac{x-5}{3}=\frac{1-y}{5}=\frac{1-z}{2}\). Find the equation of plane \(q\) in cartesian form.[3]
Find the position vector of the point which is a reflection of \(A\) in the line of intersection between \(p\) and \(q\).[6]
Video solution locked
A free account saves your progress; this video needs a course plan.
680+ questions here come with free worked solutions. A free account saves your questions and progress; this one needs a course plan.
Create a free account to practise similar questions.
Need help? Join our JC Math tuition classes.
Learn more