2020 VJC J1 MYE Q8

2020 VJC J1 MYE Q8

8 marks
Mid Year Exam
  1. Find the exact roots of the equation \(2\left| {{x}^{2}}-12x \right|=x+3\).[4]
  2. On the same axes, sketch the curves with equations \(y=2\left| {{x}^{2}}-12x \right|\) and \(y=x+3\).
    Hence solve exactly the inequality \(2\left| {{x}^{2}}-12x \right|\le x+3\).[4]

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Answer:(i) \(\frac{25\pm \sqrt{649}}{4}\)and \(\frac{23\pm \sqrt{505}}{4}\) (ii) \(\frac{25-\sqrt{649}}{4}\le x\le \frac{23-\sqrt{505}}{4}\) or \(\frac{23+\sqrt{505}}{4}\le x\le \frac{25+\sqrt{649}}{4}\)

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