Relative to the origin \(O\), the points \(A\) and \(B\) have position vectors \(\mathbf{a}\) and \(\mathbf{b}\) respectively, where \(\mathbf{a}\) and \(\mathbf{b}\) are non-zero vectors.
It is given that \(\mathbf{a}\times \mathbf{b}=\mathbf{0}\). Find \(\mathbf{a}\cdot \mathbf{b}\) in terms of \(\left| \mathbf{b} \right|\).[2]
It is now given that \(\mathbf{a}\times \mathbf{b}\ne \mathbf{0}\). Point \(P\) is the foot of the perpendicular from \(A\) to the line \(OB\) and the point \(Q\) is the foot of the perpendicular from \(B\) to the line \(OA\). It is given that \(AP=BQ\).
Write down the lengths \(AP\) and \(BQ\) in terms of \(\mathbf{a}\) and \(\mathbf{b}\).[2]
Hence show that \(\left| \mathbf{a} \right|=\left| \mathbf{b} \right|\).[1]
Given also that the angle between \(\mathbf{a}\) and \(\mathbf{a}-\mathbf{b}\) is \(\phi \) radians, show that \(\mathbf{a}\cdot \mathbf{b}=-{{\left| \mathbf{a} \right|}^{2}}\cos \,2\phi \).[2]
The pyramid \(ORST\) has a triangular base \(ORS\) and height \(OT\). The position vectors of \(R\) and \(S\) are \(-4\mathbf{i}+\mathbf{j}+3\mathbf{k}\) and \(5\mathbf{i}+\mathbf{j}\) respectively. Find the possible coordinates of \(T\) if the volume of the pyramid \(ORST\) is \(35\) units\(^{3}\).[5]
[Volume of pyramid \(=\frac{1}{3}\times \)base area\(\times \)height]
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Default solution
Answer:(a) n = (-3, -15, -9); (b) T = (-2, -10, -6) or (2, 10, 6)