2020 SAJC P1 Q1

2020 SAJC P1 Q1

5 marks
Prelims

It is given that \(\mathrm{f}\left( x \right)=-4{{x}^{2}}+12x+7\).

  1. Sketch the graph of \(y=\mathrm{f}\left( \left| x \right| \right)\), stating the coordinates of turning point(s) and of point(s) where \(y=\mathrm{f}\left( \left| x \right| \right)\) crosses the axes.[3]
  2. Solve the inequality \(-4{{x}^{2}}+12\left| x \right|+7\le 4x+7\).[2]

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Answer:(ii) \(x\le -4\) or \(x=0\) or \(x\ge 2\)

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