2020 ASRJC P1 Q5(a) | 2024 SAJC P1 Q8b

2020 ASRJC P1 Q5(a) | 2024 SAJC P1 Q8b

Junior College 2
14 marks

A graphing calculator is not allowed for this question.

  1. Find the square roots of \(2\mathrm{i}\).[2]
  2. Solve the equation \(w^2 = 3 - 4\mathrm{i}\). Hence find the roots of the equation \(z^2 - 4\mathrm{i}z + 4\mathrm{i} - 7 = 0\), giving your answers in Cartesian form.[6]
  3. Given that \(w = \frac{1}{2 + \mathrm{i}\alpha}\) where \(\alpha \in \mathbb{R}\), and \(w^*\) denotes the complex conjugate of \(w\), find \(ww^*\) and hence prove that \(w + w^* = 4ww^*\) ---(1).
    The complex number \(w\) is represented in an Argand diagram by the point \(A\). By using (1) and considering \(w = x + y\mathrm{i}\), where \(x, y \in \mathbb{R}\), show that, \(A\) lies on a circle as \(\alpha\) varies. Find the Cartesian equation of this circle, stating clearly its centre and radius.[6]

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Answer:(a) \(1+\mathrm{i}\), \(-1-\mathrm{i}\) (b) \(w=2-\mathrm{i}\) or \(w=-2+\mathrm{i}\), \(z=2+\mathrm{i}\) or \(z=-2+3\mathrm{i}\) (c) \(ww^*=\dfrac{1}{4+\alpha^2}\), circle \(\left(x-\dfrac14\right)^2+y^2=\dfrac1{16}\), centre \(\left(\dfrac14,0\right)\), radius \(\dfrac14\)

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