2020 ACJC Promo Q4

2020 ACJC Promo Q4

5 marks
Promo

Sketch the graphs of \(y=\left| x \right|\) and \(y=\frac{c}{x-c}\), where \(c>0\), on the same diagram, stating clearly the coordinates of any points where the curves cross the axes.[2]

Solve the equation

\(\left| x \right|=\frac{c}{x-c}\),

leaving your answer in terms of \(c\).[2]

Hence solve the inequality \(\left| x \right|>\frac{c}{\left| x \right|-c}.\)[1]

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Answer:\(x = (c + √(c² + 4c))/2; Inequality: x > (c + √(c² + 4c))/2 or x < -(c + √(c² + 4c))/2 or -c < x < c\)

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