2020 ACJC PROMO Q3

2020 ACJC PROMO Q3

5 marks
Promo

A curve \(C\) has equation \({{\left( y-kx \right)}^{2}}+8y-12=0\), where \(k\) is a real constant.

  1. Find \(\frac{\mathrm{d}y}{\mathrm{d}x}\) in terms of \(x,y\) and \(k\).[2]
  2. The tangent to \(C\) at the point where \(x=2\) is parallel to the \(y\)-axis. Find the value of \(k\).[3]

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Answer:(i) \(\frac{dy}{dx}= rac{k(y-kx)}{y-kx+4}\); (ii) \(k= rac74\)

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