The point \(M\) has position vector relative to the origin \(O\), given by \(6\mathbf{i}-5\mathbf{j}+11\mathbf{k}\). The line \({{l}_{1}}\) has equation \(x-7=\frac{y}{3}=\frac{z+2}{-2}\), and the plane \(\pi \) has equation \(4x-2y-z=30\).
The point \(N\) is the foot of perpendicular from \(M\) to \({{l}_{1}}\). The line \({{l}_{2}}\) is the line passing through \(M\) and \(N\).
Video solution locked
Sign in to view the step-by-step solution
Need help? Join our JC Math tuition classes.
Learn more