2019 RGS Y1 EYA Q18

2019 RGS Y1 EYA Q18

IP 1
10 marks

Answer the whole of this question on a piece of graph paper.

The taxi fare, \(\$y\), charged by Taxi Company A, for a journey is given by \(y=4+0.55x\), where \(x\) is the distance travelled in km. Some corresponding values of \(x\) and \(y\) are given in the following table:

Distance, \(x\) (km)21220
Taxi fare, \(\$y\)5.1\(p\)15
    1. Find the value of \(p\).[1]
    2. Using a scale of \(1\) cm to represent \(2\) units on the \(x\)-axis and \(1\) cm to represent \(1\) unit on the \(y\)-axis, draw the graph of \(y=4+0.55x\) for \(0\le x\le24\).[3]
    3. Explain the significance of the number \(4\) in the given context.[1]
  1. The charges of Taxi Company B can be modelled by the equation \(y=6+0.3x\).
    1. Explain what the number \(0.3\) means in the given context.[1]
    2. By adding another line on the same axes drawn in (a), find the solution to the simultaneous equations \(y=4+0.55x\) and \(y=6+0.3x\).[3]
    3. Use your graphs to advise your friend who wants to hire a taxi from one of these two companies.[1]

Solution:

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Answer:(a)(i) \(10.6\) (iii) \(\$4\) base fare (b)(i) \(\$0.30\) per km (ii) \((8,8.4)\) (iii) A for \(x<8\), B for \(x>8\); equal at \(x=8\)

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