In the figure, $ABCD$ is a square and $ABF$ is an isosceles triangle so that $AB=AF$. \(A

Question

In the figure, $ABCD$ is a square and $ABF$ is an isosceles triangle so that $AB=AF$. $AEC$ and $DEF$ are straight lines. Given that $\angle EAF=22^\circ$, find $\angle BFA$.[3] show that $\triangle ADF$ is an isosceles triangle, and hence find $\angle CDF$.[3] find $\angle AEF$. State your reasons clearly.[2]

Accepted Answer

(i) $78.5^\circ$ (ii) $33.5^\circ$ (iii) $101.5^\circ$

2019 RGS Y1 EYA Q13

2019 RGS Y1 EYA Q13

Solution:

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