2019 NYJC P1 Q7

2019 NYJC P1 Q7

9 marks
Prelims
Free

A spherical tank with negligible thickness and internal radius \(a\)cm contains water. At time \(t\)s, the water surface is at a height \(x\)cm above the lowest point of the tank and the volume of water in the tank, \(V\)cm\(^{3}\), is given by \(V=\frac{1}{3}\pi {{x}^{2}}\left( 3a-x \right)\). Water flows from the tank, through an outlet at its lowest point, at a rate \(\pi k\sqrt{x}\)cm\(^{3}\) s\(^{-1}\), where \(k\) is a positive constant.

  1. Show that \(\left( 2ax-{{x}^{2}} \right)\frac{\mathrm{d}x}{\mathrm{d}t}=-k\sqrt{x}\).[2]
  2. Find the general solution for \(t\) in terms of \(x\),\(a\) and \(k\).[3]
  3. Find the ratio \({{T}_{1}}:{{T}_{2}}\), where \({{T}_{1}}\) is the time taken to empty the tank when initially it is completely full, and \({{T}_{2}}\) is the time taken to empty the tank when initially it is half full.[4]

Video Solution:

Default solution

Timothy Gan
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Answer:(i) \((2ax-x^2)\frac{\mathrm dx}{\mathrm dt}=-k\sqrt{x}\) (ii) \(t=\frac{1}{k}\left[ c-\frac{4}{3}a{{x}^{\frac{3}{2}}}+\frac{2}{5}{{x}^{\frac{5}{2}}} \right]\) (iii) Ratio\(=8\sqrt{2}:7\)

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