2019 NYJC P1 Q3

2019 NYJC P1 Q3

6 marks
Prelims

Without using a calculator, solve the inequality \(\frac{{{x}^{2}}-3x+4}{x+2}\ge 2x+1\). Hence solve the inequality \(\frac{{{a}^{2x}}+3{{a}^{x}}+4}{{{a}^{x}}-2}\le 2{{a}^{x}}-1\) where \(a>2\).[6]

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Answer:(i) \(x \leq -4 - 3\sqrt{2}\) or \(-2 < x \leq -4 + 3\sqrt{2}\) (ii) \(x \geq \frac{\ln(4 + 3\sqrt{2})}{\ln a}\) or \(x < \frac{\ln 2}{\ln a}\)

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