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2019 NJC C1BT Q3
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2019 NJC C1BT Q3
7 marks
Mid Year Exam
Free
Using a graphical method, solve the inequalities \(-3<\left| {{x}^{2}}-1 \right|-\left| x+3 \right|<3\).
[3]
Without using a calculator, solve the inequality \(\frac{{{x}^{2}}+1}{x+3}\le 1\).
[4]
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Answer:
(a) -2.19 < x < 0.618 or 1.62 < x < 3.19; (b) x < -3 or -1 ≤ x ≤ 2
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