It is given that
\({\mathrm{f}(x) = \begin{cases} 4a^2 - x^2, & \mathrm{for } \ 0 < x \leq 2a, \\ 2a(x - 2a), & \mathrm{for } \ 2a < x \leq 4a, \end{cases}}\)
and that \(\mathrm{f}(x)=\mathrm{f}(x+4a)\) for all real values of \(x\), where \(a\) is a positive real constant.
The function \(\mathrm{g}\) is defined by
\(\mathrm{g}:x\mapsto \sqrt{4{{a}^{2}}-{{(x-2a)}^{2}}}\), \({2a < x < 4a}\).
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