2019 EJC P2 Q2

2019 EJC P2 Q2

6 marks
Prelims

The diagram shows a mechanism for converting rotational motion into linear motion. The point \(P\) is on the circumference of a disc of fixed radius r which can rotate about a fixed point \(O\). The point \(Q\) can only move on the line \(OX\), and \(P\) and \(Q\) are connected by a rod of length \(2r\). As the disc rotates, the point \(Q\) is made to slide along \(OX\). At time t, angle \(POQ\) is \(\theta\) and the distance \(OQ\) is \(x\).

  1. State the maximum and minimum values of \(x\).[1]
  2. Show that \(x=r\left( \cos \theta +\sqrt{4-{{\sin }^{2}}\theta } \right)\).[2]
  3. At a particular instant, \(\theta =\frac{\pi }{6}\) and \(\frac{\mathrm{d}\theta }{\mathrm{d}t}=0.3\). Find the numerical rate at which point \(Q\) is moving towards point \(O\) at that instant, leaving your answer in terms of \(r\).[3]

Video Solution:

Video Solution

Video solution locked

A free account saves your progress; this video needs tuition enrolment.

Solution:

Solution locked

680+ questions here come with free worked solutions. A free account saves your questions and progress; this one needs tuition enrolment.

Create a free account to practise similar questions.

Answer:(i) maximum \(3r\), minimum \(r\); (ii) \(x=r(\cos\theta+\sqrt{4-\sin^2\theta})\); (iii) \(\frac{dx}{dt}=-0.217r\)

Need help? Join our JC Math tuition classes.

Learn more