The equations of two planes \({{P}_{1}}\) and \({{P}_{2}}\) are \(x-2y+3z=4\) and \(3x+2y-z=4\) respectively.
The equation of a third plane \({{P}_{3}}\) is \(5x-ky+6z=1\), where \(k\) is a constant.
Use the value of \(k\) found in part (ii) for the rest of the question.
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