2019 ASRJC Promo Q5
2019 ASRJC Promo Q5
3 marks
Promo
- (b) If \(0 < a < 1\), find \(\displaystyle\displaystyle \displaystyle\int_{0}^{1}{\left( a+x \right)\left| a-x \right|\,}\mathrm{d}x\), leaving your answer in terms of \(a\).[3]
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Answer:\(\frac{4{{a}^{3}}}{3}-{{a}^{2}}+\frac{1}{3}\)
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