2018 TMJC P2 Q5

2018 TMJC P2 Q5

7 marks
Prelims

An unbiased die has three faces painted red, two faces painted green and one face painted blue. A red face has a score of \(1\) point, a green face has a score of \(2\) points and a blue face has a score of \(3\) points.

Two such dice are thrown and the sum of their scores is denoted by \(X\).

  1. Show that \(\mathrm{P}\left( X=4 \right)=\frac{5}{18}\) and find the probability distribution of \(X\).[3]
  2. Find \(\mathrm{E}\left( X \right)\) and show that \(\mathrm{Var}\left( X \right)=\frac{10}{9}\).[2]

Suppose now a red face has a score of \(3\) points, a green face has a score of \(2\) points and a blue face has a score of \(1\) point.

  1. Deduce the expectation and variance of the sum of scores obtained from a throw of two such dice.[2]

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Answer:(ii) \(\mathrm{E}(X) = \dfrac{10}{3}\); (iii) \(\mathrm{E}(Y) = \dfrac{14}{3}\), \(\mathrm{Var}(Y) = \dfrac{10}{9}\)

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