2018 SAJC MYE BT2 P1 Q5

2018 SAJC MYE BT2 P1 Q5

8 marks
Mid Year Exam

The graph of \(y=2\ln x-{{\left( \ln x \right)}^{2}}\) where \(x>0\) is shown in the diagram below. The graph cuts the \(x\)-axis at \(x=1\) and \(x={{e}^{2}}\).

The function \(\mathrm{f}\) is defined by

\(\mathrm{f}:x\mapsto 2\ln x-{{\left( \ln x \right)}^{2}},\)\(0 < x\le a,\)

where \(a\) is a constant.

Find the greatest possible value of \(a\) for which \({{\mathrm{f}}^{-1}}\) exists, giving your answer in exact form. Hence, find \({{\mathrm{f}}^{-1}}\) in similar form.[6]

The function \(\mathrm{g}\) is defined by

\(\mathrm{g}:x\mapsto \frac{1}{3}{{e}^{x}}\), \(x\in \mathbb{R}\) .

Find the exact range of the composite function \(\mathrm{g}{{\mathrm{f}}^{-1}}\).[2]

Video Solution:

Video Solution

Video solution locked

A free account saves your progress; this video needs a course plan.

Solution:

Solution locked

680+ questions here come with free worked solutions. A free account saves your questions and progress; this one needs a course plan.

Answer:\(a = \mathrm{e}\); \(\mathrm{f}^{-1}(x) = \mathrm{e}^{1-\sqrt{1-x}}\), \(x \leq 1\); \(R_{\mathrm{gf}^{-1}} = \left(\dfrac{1}{3}, \dfrac{1}{3}\mathrm{e}^{\mathrm{e}}\right]\)

Need help? Join our JC Math tuition classes.

Learn more