When a solid turns into a gas without first becoming a liquid, the process is called sublimation. As

Question

When a solid turns into a gas without first becoming a liquid, the process is called sublimation. As a spherical mothball sublimes, its volume, in cm$^{3}$, decreases at a rate, in cm$^{3}$ per day, proportional to its surface area.

Show that the radius of the mothball decreases at a constant rate.[3]

[It is given that a sphere of radius $r$ has surface area $4\pi {{r}^{2}}$ and volume $\frac{4}{3}\pi {{r}^{3}}$.]

Accepted Answer

$Radius decreases at constant rate $k$ cm per day$

2018 RI P2 Q1

2018 RI P2 Q1

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