2018 RGS IP2 EOY Q12

2018 RGS IP2 EOY Q12

IP 2
8 marks

In the diagram \(\mathrm{BDZ}, \mathrm{CZA}\) and \(\mathrm{CYXB}\) are straight lines. \(CY = YX = XB\) and \(YZ\) is parallel to \(XA\).

  1. State a triangle similar to triangle \(\mathrm{CYZ}\)

    [1]
  2. Find the length of \(\mathrm{YZ}\) if \(\mathrm{XA} = 20\) cm.

    [2]
  3. Find,

    1. \(\frac{\text{Area of}\hspace{0.5em} \triangle \mathrm{XBD}}{\text{Area of}\hspace{0.5em} \triangle \mathrm{YBZ}}\),

      [1]
    2. \(\frac{\text{Area of}\hspace{0.5em} \triangle \mathrm{CZY}}{\text{Area of}\hspace{0.5em} \triangle \mathrm{YBZ}}\),

      [1]
    3. \(\frac{\text{Area of}\hspace{0.5em} \triangle \mathrm{ADZ}}{\text{Area of}\hspace{0.5em} \mathrm{DXCZ}}\),

      [3]

Solution:

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Answer:(i) \(\triangle CXA\). (ii) \(10\) cm. (iii)(a) \(1/4\), (b) \(1/2\), (c) \(3/5\).

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