The random variable \(X\) has a normal distribution with mean \(\mu \) and standard deviation \(2\).
Given further that \({\mathrm{P}(X > 3k) = \mathrm{P}(X < 9k + 4)}\) and using the answer obtained in part (i), find the value of \({k}\).
[1]The random variable \(Y\) is related to \(X\) by the formula \(Y=10-X\).
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