2018 EJC Promo Q6

2018 EJC Promo Q6

7 marks
Promo

A curve \(D\) has parametric equations \(x=a\theta -a\sin \theta \), \(y=a-a\cos \theta \), where \(a>0\) and \(0<\theta <\pi \).

  1. Show that \(\frac{\mathrm{d}y}{\mathrm{d}x}=\cot \frac{\theta }{2}\).[3]
  2. Find the exact equation of the normal to the curve at the point for which \(\theta =\frac{\pi }{3}\).[4]

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Answer:\(y = -\dfrac{1}{\sqrt{3}}x + \dfrac{a\pi}{3\sqrt{3}}\)

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