2018 ACJC P2 Q6

2018 ACJC P2 Q6

8 marks
Prelims

On average, \(40\%\) of Christmas tree light bulbs manufactured by a company are red and the rest are blue. The lights are sold in boxes of \(20\). Assume that the number of red light bulbs in a box has a binomial distribution.

  1. Find the probability that a box of \(20\) light bulbs contains fewer red light bulbs than blue light bulbs.[1]
  2. In \(n\) randomly chosen boxes, the probability that there will be at least \(2\) boxes with fewer red light bulbs than blue is at most \(0.999\). Find the greatest value of \(n\).[3]
  3. A random sample of \(50\) boxes is chosen. Using an approximate distribution, find the probability that the mean number of red light bulbs in \(1\) box will not exceed \(7.5\).[3]
  4. A customer selects boxes of light bulbs at random from a large consignment until she finds a box with fewer red lights than blue. Give a reason why a binomial distribution is not an appropriate model for the number of boxes selected.[1]

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Answer:(i) \({0.755}\) (ii) \({7}\) (iii) \({0.0533}\) (iv) In the context of the question, the number of boxes that the customer can select is not fixed (sample size is not fixed). Hence a binomial distribution is not an appropriate model as it requires a fixed number of trials.

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