2017 TJC MYE Q4

2017 TJC MYE Q4

12 marks
Mid Year Exam

\(ABCD\) is a piece of cardboard in the shape of a trapezium with \(\angle COA=\angle BAO={{90}^{\circ }}\), \(OA=5\)cm, \(OC=\frac{5\sqrt{2}}{3}\)cm and \(AB=5\sqrt{2}\) cm.

As part of a model for a structure, this cardboard is placed on a flat floor with \(OA\) touching the floor and \(B\) being at a height of \(5\)cm vertically above the floor.

The flat floor is assumed to be the \(x-y\) plane and the positive \(z\)-axis in the vertically upwards direction.

The position of \(O\) on the ground is taken to be the origin and \(A\) has coordinates \(\left( 3,4,0 \right)\).

  1. Show that a possible coordinates of \(B\) is \(\left( 7,1,5 \right)\).[5]

Use \(\left( 7,1,5 \right)\) as the coordinates of \(B\) for the rest of the question.

  1. Find the position vector of \(C\).[2]
  2. Find a vector equation of line \(BC\).[2]
  3. Find the acute angle between \(BC\) and the floor.[3]

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Answer:(i) B = (7, 1, 5); (ii) OC = (1/3)(4, -3, 5); (iii) r = (7, 1, 5) + λ(17, 6, 10); (iv) 29.0°

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