A car is travelling at a speed of \(30\)m/s on a road heading towards a perpendicular train track, which is elevated \(30\) m above the ground. The front of the car is \(40\) m away form the track when the front o the train first crossed the road.
If the train is travelling at \(20\)m/s, show that the distance between the front of the train and the car is \(\sqrt{1300{{t}^{2}}-2400t+2500}\) m.[2]
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