2020 NYJC P1 Q7

2020 NYJC P1 Q7

Junior College 2
5 marks

The curve \(C\), where \(y \ge 0\), is such that it satisfies the following differential equation

\[(1+x^2)y \frac{\mathrm{d}y}{\mathrm{d}x} + 2xy^2 = 0,\]

where \(y = 1\) when \(x = 0\).

By using the substitution \(z = y^2\), solve the differential equation and find the value of \(y\) when \(x = 1\).[5]

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Answer:\(y=\dfrac1{1+x^2}\) When \(x=1\), \(y=\dfrac12\)

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