2017 MJC Promo Q2
2017 MJC Promo Q2
6 marks
Promo
A closed cylinder with a circular base has radius \(r\) cm and fixed height \(h\) cm. Given that its volume \(V\) is increasing at a rate twice as fast as its surface area \(A\), with respect to time \(t\), show that \(r=\frac{2h}{h-4}\). Hence show that \(h>4\).[6]
Video Solution:
Video solution locked
A free account saves your progress; this video needs tuition enrolment.
Solution:
Solution locked
680+ questions here come with free worked solutions. A free account saves your questions and progress; this one needs tuition enrolment.
Create a free account to practise similar questions.
Answer:\(r = \displaystyle\frac{2h}{h-4}\), \(h > 4\)
Need help? Join our JC Math tuition classes.
Learn more