A fund is started at \(\$6000\) and compound interest of \(3\%\) is added to the fund at the end of each year. If withdrawals of \(\$k\) are made at the beginning of each of the subsequent years, show that the amount in the fund at the beginning of the \(\left( n+1 \right)\)th year is
\(\mathrm{}\!\!\$\!\!\mathrm{}\frac{100}{3}\left[\left(180-k\right){{\left(1.03\right)}^{n}}+k\right]\).[5]





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