2017 HCI P2 Q6

2017 HCI P2 Q6

6 marks
Prelims

A biased tetrahedral (\(4\)-sided) die has its faces numbered ‘\(-1\)’, ‘\(0\)’, ‘\(2\)’ and ‘\(3\)’. It is thrown onto a table and the random variable \(X\) denotes the number on the face in contact with the table. The probability distribution of \(X\) is as shown.

\(x\)\(-1\)\(0\)\(2\)\(3\)
P (\(X = x\))\({\frac{1}{8}}\)\({\frac{1}{2}}\)\({\frac{1}{8}}\)\({\frac{1}{4}}\)
  1. The random variable \(Y\) is defined by \({{X}_{1}}+{{X}_{2}}\), where \({{X}_{1}}\) and \({{X}_{2}}\) are \(2\) independent observations of \(X\). Show that \(\mathrm{P}\left( Y=2 \right)=\frac{3}{16}\).[2]
  2. In a game, a player pays \(\$2\) to throw two such biased tetrahedral dice simultaneously on a table. For each die, the number on the face in contact with the table is the score of the die. The player receives \(\$16\) if the maximum of the two scores is \(-1\), and receives \(\$3\) if the sum of the two scores is prime. For all other cases, the player receives nothing. Find the player’s expected gain in the game.[4]

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Answer:\(\mathrm{E}(G)=-\$0.25\)

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