Without using a calculator, solve the inequality $\frac{x+2}{x-1}\le \frac{x}{x+3}$. [4] Hence find

Question

Without using a calculator, solve the inequality $\frac{x+2}{x-1}\le \frac{x}{x+3}$. [4] Hence find the set of values of $x$ for which $\frac{{{e}^{x}}+2}{{{e}^{x}}-1}\le \frac{{{e}^{x}}}{{{e}^{x}}+3}$ . [2]

Accepted Answer

(i) $x<-3$ or $-1\leq x<1$ (ii) $x<0$

2017 HCI P1 Q1

2017 HCI P1 Q1

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