2016 VJC Promo Q10

2016 VJC Promo Q10

14 marks
Promo
    1. Find \(\displaystyle\displaystyle \displaystyle\int{\frac{2-x}{\sqrt{(4x-{{x}^{2}}-1)}}\,\mathrm{d}x}\).[2]
    2. Find \(\displaystyle\displaystyle \displaystyle\int{\frac{1}{\sqrt{(4x-{{x}^{2}}-1)}}\,\mathrm{d}x}\).[2]
    3. Using the results of part (i) and (ii), find \(\displaystyle\displaystyle \displaystyle\int{\frac{x}{\sqrt{(4x-{{x}^{2}}-1)}}\,\mathrm{d}x}\).[2]
    1. By using the substitution \(u=\sqrt{x}\), find \(\displaystyle\displaystyle \displaystyle\int{\frac{\sqrt{x}}{1+\sqrt{x}}\,\mathrm{d}x}\).[4]
    2. Find the exact value of \(\displaystyle\displaystyle \displaystyle\int_{0}^{9}{\ln \left( 1+\sqrt{x} \right)\,\mathrm{d}x}\), leaving your answer in the form \(a\ln b-\frac{c}{b}\), where \(a\), \(b\) and \(c\) are integers to be determined.[4]

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Answer:\(16\ln 2 - \frac{3}{2}\), \(a = 16\), \(b = 2\), \(c = 3\)

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