For events $A$ and $B$, it is given that $\mathrm{P}\left( A \right)=\frac{1}{2}$, \(\mathrm{P

Question

For events $A$ and $B$, it is given that $\mathrm{P}\left( A \right)=\frac{1}{2}$, $\mathrm{P}\left( B \right)=\frac{2}{5}$ and $\mathrm{P}\left( A|B' \right)=\frac{11}{30}$. Find $\mathrm{P}\left( A\cap B \right)$.[3] For a third event $C$, it is given that $\mathrm{P}\left( C \right)=\frac{3}{10}$. If $A$ and $C$ are mutually exclusive and $B$ and $C$ are independent, find $\mathrm{P}\left( B\cap C \right)$,[1] $\mathrm{P}\left( A'\cap B\cap C' \right)$.[2]

Accepted Answer

(i) $P(A\cap B)=\frac7{25}$ (ii) $P(B\cap C)=\frac3{25}$ (iii) $P(A'\cap B\cap C')=0$

2015 RI P2 Q6

2015 RI P2 Q6

Video Solution:

Solution:

Solution locked