For events \(A\) and \(B\), it is given that \(\mathrm{P}\left( B \right)=\frac{7}{27}\), \(\mathrm{P}\left( B|A \right)=\frac{2}{9}\) and \(\mathrm{P}\left( A|B' \right)=\frac{7}{10}\).
For a third event \(C\), it is given that \(\mathrm{P}\left( B\cap C \right)=\frac{1}{18}\) and that \(A\) and \(C\) are mutually exclusive.
Video solution locked
A free account saves your progress; this video needs a course plan.
680+ questions here come with free worked solutions. A free account saves your questions and progress; this one needs a course plan.
Create a free account to practise similar questions.
Need help? Join our JC Math tuition classes.
Learn more