It is given that the curve $C$ has equation \(y=\frac{(x-1)(x-2)}{x-3},\mathrm{ }x\in \mathbb{R},\

Question

It is given that the curve $C$ has equation $y=\frac{(x-1)(x-2)}{x-3},\mathrm{ }x\in \mathbb{R},\mathrm{ }x\ne 3.$ Use an algebraic method to find exactly the set of values that $y$ can take.[4]

Accepted Answer

$y\le 3-2\sqrt{2}$ or $y\ge 3+2\sqrt{2}$

2015 NJC P1 Q7 (a)

2015 NJC P1 Q7 (a)

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