For independent events \(A\) and \(B\), it is given that \(\mathrm{P}(A\cap B)=0.05\) and \(\mathrm{P}\left( A\cup B \right)=0.55\).
For a third event \(C\), \(\mathrm{P}\left( C \right)=0.5\) and \(\mathrm{P}\left( A'\cup B'|C \right)=0.95\).
Video solution locked
A free account saves your progress; this video needs a course plan.
680+ questions here come with free worked solutions. A free account saves your questions and progress; this one needs a course plan.
Create a free account to practise similar questions.
Need help? Join our JC Math tuition classes.
Learn more