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<p>The diagram shows the graph of $y=\mathrm{f}(x)$. The graph has a minimum point at $(-1,-1)$ and a maximum point at $(-4,-7)$. It intersects the axes at $x=-2,\mathrm{ }x=1$ and $y=-\dfrac{2}{3}$. The equations of the asymptotes are $y=x-2$ and $x=-3$. Sketch the graph of $y=\frac{1}{\mathrm{f}(x)},$ giving the coordinates of any stationary points, points of intersection with the axes and the equations of any asymptotes.<span class="inline-marks">[3]</span></p>

The diagram shows the graph of $y=\mathrm{f}(x)$. The graph has a minimum point at $(-1,-1)$ and a maximum point at $(-4,-7)$. It intersects the axes at $x=-2,\mathrm{ }x=1$ and $y=-\dfrac{2}{3}$. The equations of the asymptotes are $y=x-2$ and $x=-3$. Sketch the graph of $y=\frac{1}{\mathrm{f}(x)},$ giving the coordinates of any stationary points, points of intersection with the axes and the equations of any asymptotes.

Reciprocal Graph, $y=\frac{1}{f(x)}$

Transformations of Graphs

International Baccalaureate Mathematics: Analysis and Approaches Higher Level

2015 DHS P1 Q5 [Modified]

2015 DHS P1 Q5 [Modified]

Video Solution:

Solution:

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