2014 SAJC P2 Q4 [Modified]

2014 SAJC P2 Q4 [Modified]

Prelims
  1. Find the complex number \(z\) in the form \(x+y\,\mathbf{i}\) where \(x\), \(y\in \mathbb{R}\) such that
    \(\frac{\mathbf{i}z}{z-2{{z}^{*}}-2}=-1\).[3]
  2. Show that that for any complex number \(z=r{{\mathrm{e}}^{\mathbf{i}\theta }}\), where \(r>0\) and \(-\pi <\theta \le \pi \),
    \(\frac{z}{z-r}=\frac{1}{2}-\frac{1}{2}\mathbf{i}\cot \left( \frac{\theta }{2} \right)\).[2]

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Answer:(a) \(z = -3 + \mathrm{i}\)

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