2013 YJC P1 Q7
2013 YJC P1 Q7
11 marks
Prelims
The equation of a curve is \({{y}^{2}}-xy=-1\).
- Find the equations of all tangents to the curve that are parallel to the \(y\)-axis[4]
- State and justify whether the curve has any stationary points.[2]
- Find the area of the region bounded by the axes, and the normal to the curve at the point where the \(y\)-coordinate is \(2\).[5]
Video Solution:
Video solution locked
A free account saves your progress; this video needs tuition enrolment.
Solution:
Solution locked
680+ questions here come with free worked solutions. A free account saves your questions and progress; this one needs tuition enrolment.
Create a free account to practise similar questions.
Answer:(i) \({x = 2}\) and \({x = -2}\) (ii) no stationary points. (iii) \(10.0\)
Need help? Join our JC Math tuition classes.
Learn more