2013 SAJC P1 Q6

2013 SAJC P1 Q6

9 marks
Prelims

With respect to the origin \(O\), the position vectors of the points \(A\) and \(B\) are \(-3\mathbf{i}+2\mathbf{j}+m\mathbf{k}\) and \(-12\mathbf{i}+8\mathbf{j}+4\mathbf{k}\) respectively, where \(m<0\). The point \(P\) is on line \(AB\) such that \(AP:PB=2:1\).

  1. Find the coordinates of point \(P\) in terms of \(m\).[2]
  2. It is given that the area of triangle \(OAP\) is \(4\sqrt{13}\) units\(^{2}\). Show that \(m=-2\).[4]
  3. Hence, or otherwise, the shortest distance from \(O\) to the line \(AP\).[3]

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Answer:(i) \(\left(-9,6,\dfrac{m+8}{3}\right)\) (ii) \(m=-2\) (iii) \(3.50\) units

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