Given that $y={{ an }^{-1}}\sqrt{x}$, find $\frac{\mathrm{d}y}{\mathrm{d}x}$. [2] Given that $\sqrt

Question

Given that $y={{	an }^{-1}}\sqrt{x}$, find $\frac{\mathrm{d}y}{\mathrm{d}x}$. [2] Given that $\sqrt[x]{y}=\sqrt[y]{x}$, where $x>0$, $y>0$, find $\frac{\mathrm{d}y}{\mathrm{d}x}$ . [4]

Accepted Answer

$\dfrac{1}{2\sqrt{x}(1+x)}$ (b) $\dfrac{1+\ln x}{1+\ln y}$

2013 Promo CJC Q4

2013 Promo CJC Q4

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