It is given that $y={{e}^{-x}}$, $y={{e}^{2x}}$ and $y={{e}^{-3x}}$ are solutions to the differentia

Question

It is given that $y={{e}^{-x}}$, $y={{e}^{2x}}$ and $y={{e}^{-3x}}$ are solutions to the differential equation $\frac{{{\mathrm{d}}^{3}}y}{\mathrm{d}{{x}^{3}}}+a\frac{{{\mathrm{d}}^{2}}y}{\mathrm{d}{{x}^{2}}}+b\frac{\mathrm{d}y}{\mathrm{d}x}+cy=0$. Find the values of the constants $a$, $b$ and $c$.

Accepted Answer

$a = 2, b = -5, c = -6$

2013 NJC SH1 Promo Q1

2013 NJC SH1 Promo Q1

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