There are two particles \(A\) and \(B\) with particle \(A\) at \(\left( -13,\ 0 \right)\) and particle \(B\) at \(\left( 0,\ -9 \right)\) with respect to origin \(O\). \(A\) moves towards \(O\) at a constant speed of \(u\ \mathrm{cm}\,{{\mathrm{s}}^{-1}}\) in the positive \(x\) direction and \(B\) moves towards \(O\) at a constant speed of \(\frac{4}{3}u\ \mathrm{cm}\,{{\mathrm{s}}^{-1}}\) in the positive \(y\)-direction (see diagram).
Show that, after a time of \(t\) seconds, the distance between \(A\) and \(B\) is given by
\(\sqrt{\left( \frac{25}{9}{{u}^{2}}{{t}^{2}}-50ut+250 \right)}\) cm.[2]
Find the coordinates of \(A\) and \(B\) at the instant when the two particles are closest.[4]
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